X^2+10x-1080=0

Solution for X^2+10x-1080=0 equation:

X^2+10X-1080=0

a = 1; b = 10; c = -1080;
Δ = b2-4ac
Δ = 102-4·1·(-1080)
Δ = 4420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4420}=\sqrt{4*1105}=\sqrt{4}*\sqrt{1105}=2\sqrt{1105}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{1105}}{2*1}=\frac{-10-2\sqrt{1105}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{1105}}{2*1}=\frac{-10+2\sqrt{1105}}{2}
$